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Usually need lossless integer math for cryptography to work. So the form might be similar, but you’re working over finite fields (ie of integers mod some number
by Robotbeat 5y ago
Usually need lossless integer math for cryptography to work. So the form might be similar, but you’re working over finite fields (ie of integers mod some number), not real numbers.
(Okay, I have only a tenuous understanding of this myself. I’m a physicist, not a mathematician! Mathematicians are intimidating.)
- lamontcg 5y agoYeah that's where I should have taken abstract algebra in college (I did get up to graduate level QM though in physics).