3 ms·
Up to 1024 bit is considered to be broken (not mathematically but at least by means of brute force) against state actors in a targeted attack.
by SnowHill9902 5y ago
Up to 1024 bit is considered to be broken (not mathematically but at least by means of brute force) against state actors in a targeted attack.
- dagenix 5y agoWhat do you mean by "brute force"? Find a collision? I think it's almost certain the combined resources of every computer ever made would be unable to brute force a collision in a 1024 bit hash.
- staticassertion 5y agoThat does not sound right. Are you talking about RSA?
- wolf550e 5y agoYou're confusing symmetric and asymmetric cryptography, it's such a basic mistake that maybe you should not comment on cryptography until you've read some more. SHA-256, SHA-3-256, BLAKE2, BLAKE3, etc. are all not-broken and have "128 bits of security". 256bit ECC like NISP P-256 ECDHE, ECDSA and ECIES, X25519 ECDHE and Ed25519 EdDSA are not-broken and have "128 bits of security". RSA and FFDHE at 3072 bit are not broken and have about "128 bits of security". RSA-2048 remains very popular, although it is only about 112 bits of security. See https://security.stackexchange.com/a/230713/70830 https://security.stackexchange.com/a/230713/70830 and the links from it for more info.