4 ms·

The compiler is free to optimize this how it sees fit. Taking the address of a value doesn't necessarily move it to the heap.

• jganetsk 15y ago
  I imagine this optimization can only happen once escape analysis is performed. In the general case, address-of moves the data to the heap, or causes it to be stored on the heap in the first place. Correct?
  • enneff 15y ago
    Yes.