5 ms·

The OP is wondering why this does not work with a current gcc.

• deleted 5y ago
  [deleted]
• sargstuff 5y ago
  char --> signed 8 bits, no less/no more than 8 bits used. (*char) --> compiler will detect how to align char address for given hardware. aka, 32bit machine,there are 4 places that a byte can evenly fit in 32 bit address/pointer. May not be a gcc issue. Directly manipulating a memory address (aka the numeric location where value is stored) usually prohibited by OS (or not allowed by hardware used) for security reasons. May also be reason why works under Debian <X> and not Debian <Y>
  • sargstuff 5y ago
    The 'fun' part about minimal addressable memory sizes (assuming hardward supports) is this : if addresses are 64bits, and only 48 bits are used for addressing, there are 16 bits available for other use!
  • tom_ 5y ago
    It is a gcc issue, in that this code is written using a non-standard gcc-specific dialect of C. In standard C, -- operates on what in C terms is known as a modifiable lvalue, a value that may be used on the left hand side of an assignment expression (https://en.cppreference.com/w/c/language/value_category https://en.cppreference.com/w/c/language/value_category). And a cast returns a value that is specifically not an lvalue of any kind (https://en.cppreference.com/w/c/language/cast https://en.cppreference.com/w/c/language/cast), meaning a cast expression is not a valid operand for the -- operator.