There's no guesswork involved. The carriage return implies a semicolon. The rule is very simple and obvious in use (to me, the code you posted looks wrong - and

There's no guesswork involved. The carriage return implies a semicolon. The rule is very simple and obvious in use (to me, the code you posted looks wrong - and it is). http://golang.org/doc/go_spec.html#Semicolons http://golang.org/doc/go_spec.html#Semicolons