Even on segmented memory, `uptr` doesn't carry provenance. You still either need `with_addr` to tell the compiler that this integer aliases an existing allocati

Even on segmented memory, `uptr` doesn't carry provenance. You still either need `with_addr` to tell the compiler that this integer aliases an existing allocation, or `with_exposed_addr` to tell the compiler that you want your use-after-free bug to also have a CVE number.