3 ms·
Sure if you want to be pedantic. However even if you double the number of rounds, the number of operations required to brute force increases by only a factor of
by zarzavat 5y ago
Sure if you want to be pedantic. However even if you double the number of rounds, the number of operations required to brute force increases by only a factor of 2. Since the number of operations is likely to be a very large number already, such a change is insignificant and we can consider the brute force cost to be independent of the number of rounds which is usually a small integer.
- naniwaduni 5y agoThe only difference between 1 and 2^128 is 128 small constant factors of 2.