3 ms·
Approximately 240 sub licenses deep (2^3 ~ 10, 10^80 atoms in observable universe)
by idealmedtech 5y ago
Approximately 240 sub licenses deep (2^3 ~ 10, 10^80 atoms in observable universe)
- paxys 5y agoThat's only for the case where project A depends on project B which depends on project C which depends on project D...240 projects deep. But what if each of them has more than 1 dependency? Also you'd have to sum up the entire series, since the licenses at every level are included in the folder, not just the top-level one.
- idealmedtech 5y ago~~Yes, in my head I was considering all of those to be, in their total, the "sublicenses." Should have been better worded; but a total of 240 distinct MIT licensed dependencies in a project is the number at which MIT-2 would run out of atoms to print on.~~ Nevermind, I see your point! In reality it would be something relating to N sums of 2^k, k being highest depth dependency for each of the N projects. Obviously we're talking bounds and not exact calculations here.
- 0des 5y agoGentlemans agreement not to tell the node guys.