4 ms·
> L1 regularization has to do with minimizing error of absolute values Not quite. It has to do with minimizing the sum of absolute values of the coefficients,
by r-zip 5y ago
> L1 regularization has to do with minimizing error of absolute values
Not quite. It has to do with minimizing the sum of absolute values of the coefficients, not the error. The squared error is still the "fidelity" term in the cost function.