3 ms·
> We see that if t (end-1) is . then e is written with the character ., as if we were to pass a very large number to the function. I don't believe this is what
by Jasper_ 5y ago
> We see that if t (end-1) is . then e is written with the character ., as if we were to pass a very large number to the function.
I don't believe this is what's happening at all... e and t are pointers, and they're not being written to, just reassigned.
- Liquid_Fire 5y agoAgreed - it looks like the author misread the code. That said, the actual exploit presented later doesn't rely on this.