3 ms·
Not necessarily. The mining algorithm could hash the block once using SHA256, then use that and a fixed-size nonce as a fixed-size parameter for the ASIC-optimi
by f7ebc20c97 5y ago
Not necessarily. The mining algorithm could hash the block once using SHA256, then use that and a fixed-size nonce as a fixed-size parameter for the ASIC-optimized hash function.
- f7ebc20c97 5y agoIsn't 99% optimal good enough?
- deleted 5y ago[deleted]
- deadbeeves 5y agoA conceivable optimization would be to compute the final digest by skipping the SHA-256 step.