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> If it's Turing Complete you can't prove that it's hermetic Turing Machine model doesn’t apply to i/o so it is a meaningless statement. Bazel and Nix achieve
by dilyevsky 5y ago
> If it's Turing Complete you can't prove that it's hermetic
Turing Machine model doesn’t apply to i/o so it is a meaningless statement.
Bazel and Nix achieve this by sandboxing i/o no turing incompleteness needed (tho bazel is still purposely non-tc but for totally different reason than hermeticity)