Try thinking about the equivalent in decimal: A left shift in binary adds a 0 at the end which multiplies by 2 (binary = 2) In decimal, the equivalent, adding

Try thinking about the equivalent in decimal: A left shift in binary adds a 0 at the end which multiplies by 2 (binary = 2) In decimal, the equivalent, adding a 0 at the end, multiplies by ten (decimal = ten)