3 ms·
But it increases points of failure. What if one or probes in the chain break for some reason? I guess you build in redundancy, but it's not obvious to me that
by ALittleLight 5y ago
But it increases points of failure. What if one or probes in the chain break for some reason?
I guess you build in redundancy, but it's not obvious to me that the added complexity - probes have to send and receive instead of just send - is worth the benefit. I really have no idea about this space though.