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As former quantum physicist, I find it little troubling to read "quantum theory has reached a dead end" in specific reference to the interpretation of quantum m
by shoyer 5y ago
As former quantum physicist, I find it little troubling to read "quantum theory has reached a dead end" in specific reference to the interpretation of quantum mechanics. Most quantum physicists could not care less about how quantum mechanics is interpreted when it makes highly accurate quantitative predictions, and there are still plenty of interesting open problems for quantum theory (e.g., related to the practical design of algorithms and hardware for quantum computers).
This article also misses what is likely the leading interpretation of quantum mechanics by actual quantum physicists, namely that the measurment problem is solved by decoherence (the quantitative theory of how classical states emerge from quantum states):
https://en.wikipedia.org/wiki/Measurement_problem#The_role_of_decoherence https://en.wikipedia.org/wiki/Measurement_problem#The_role_o...
https://royalsocietypublishing.org/doi/10.1098/rsta.2011.0490 https://royalsocietypublishing.org/doi/10.1098/rsta.2011.049...
- adriand 5y agoI read somewhere that quantum mechanics is the most tested of all scientific theories. And it has been shown to be right, every time. Hawking espoused this idea he called “model dependent realism”. The idea is that every human understanding of reality is model-dependent, that is, it is not “reality” that we truly understand (we can’t) but rather in every case we have some model of reality that is useful in particular situations. For instance, we know that Newtonian physics are not “real” but they are perfectly accurate in certain situations. So they are not “wrong” when they are used in those situations, in fact, they are right. The author of the article writes, “While Einstein won a Nobel Prize for proving that light is composed of particles that we call photons, Schrödinger’s equation characterizes light and indeed everything else as wave-like radiation. Can light and matter be both particle and wave? Or neither? We don’t know.” In model dependent realism, we can ignore this apparent contradiction. In some situations the model of light as a particle is the most useful, and in others, the model where it is a wave is the most useful. We have to accept that it is not “really” either of these models, but that no matter what we do, any model we come up with for it will still just be a model.
- colordrops 5y agoApparently Hawking coined this term in 2010. Robert Anton Wilson coined a similar term, "Model Agnosticism", all the way back in 1977 in his book Cosmic Trigger: "The Copenhagen Interpretation is sometimes called "model agnosticism" and holds that any grid we use to organize our experience of the world is a model of the world and should not be confused with the world itself. Alfred Korzybski, the semanticist, tried to popularize this outside physics with the slogan, "The map is not the territory." Alan Watts, a talented exegete of Oriental philosophy, restated it more vividly as "The menu is not the meal."
- tomthe 5y ago"All models are wrong, some are useful" describes it very well for me. It still amazes me, how late I really understood this and how many intelligent people not fully understand it.
- jerrysievert 5y agohe expanded on that quite a bit in quantum psychology (1990), giving an expanded treatise on the software of the mind and how it maps our interpretation of reality. quite a good read if you liked his previous works.
- dorgo 5y ago> it is not “reality” that we truly understand (we can’t) Yes, we can only describe with models what can be observed. But it is a bad excuse for ignoring contradictions in (or between) models.
- tluyben2 5y agoWe are human and prefer elegance, so enough will continue to try to unify models anyway. I don’t buy that we cannot understand nature but this model dependent realism is fine as a practical way of working until we do understand it.
- adriand 5y ago> I don’t buy that we cannot understand nature I don’t think anyone is saying that, but in pondering this issue, I remembered how in Spanish there are two verbs for “to know”, “saber” and “conocer”. That latter verb is often explained in English as “to be familiar with”. The usage makes the point best: you can “conocer” a person but cannot “saber” them. That is, you can be acquainted with someone but you cannot truly “know” them, no matter how close you are to them. Think about it: how well do you know yourself? You live in your own head and yet you are probably surprised by some of your own reactions, or dismayed by your actions, or fearful of certain emotions. If you do not fully understand yourself then what does understanding nature even mean? I cannot inhabit the mind of my wife, let alone inhabit a photon.
- michaelwilson 5y agoHow can you be a "former quantum physicist"? Did you somehow unlearn everything that made you a quantum physicist? Maybe you meant to say "formerly paid to be a quantum physicist"? :-)
- analog31 5y agoI can't speak for the parent, but I have a physics degree from 30 years ago. Since then my career has diverged from academic physics to the point where it would take some effort to re-learn even my graduate level QM coursework, much less familiarize with current research topics. So I could see where the "former" status comes from.
- shoyer 5y agoI guess "quantum physicist" can mean either an academic credential or a job title. In my case, I have the former but no longer the later. I finished my PhD nine years ago and no longer work in the field.
- SinParadise 5y ago>How can you be a "former quantum physicist"? By disentangling himself with quantum physics. He was a quantum physicist, so I assume he knows how to do it.
- ravi-delia 5y agoI'd love if decoherence was now the dominant perspective, and I at least am largely convinced barring some huge revolution, but it would surprise me very much. In terms of my acquaintances (largely the department of my university) team "I don't care, does it matter?" takes top spot followed by equal parts collapse and decoherence. Oh, and some Bohmian people but I don't know them as well, as interesting as it would be if they were right.
- pdonis 5y ago> namely that the measurment problem is solved by decoherence I think "solved" is too strong. The Wallace paper you reference, for example, does not claim that decoherence solves the measurement problem. His claim is only the more modest one that understanding decoherence helps to clarify what the measurement problem actually is.
- japanuspus 5y agoAs a former quantum physicist who has just decided to go back into quantum computing, this was my take as well: Introductory quantum physics courses may still include wave-function collapse and all that nonsense, but I have not met many physicists who use this as a mental model. To be a bit more specific as to how _decoherence_ solves this, one way to see it is that classicality (i.e. observables having specific values) is an emergent property in the limit of near-infinite degrees of freedom in the same way that e.g. thermodynamic properties (temperature etc.) are emergent properties of classical systems in the limit of near-infinite degrees of freedom. Putting it on the edge, claiming that quantum theory is at a dead end is like claiming statistical physics is at a dead end. One of my personal favorites for how to formalize this is the work on "pointer states" by Wojciech H. Zurek. There is a freely available Physics Today articls [0], and you can find surveys of further work e.g. in the introduction of [1]. [0]: https://arxiv.org/abs/quant-ph/0306072 https://arxiv.org/abs/quant-ph/0306072 Zurek, Decoherence and the transition from quantum to classical -- REVISITED [1]: https://arxiv.org/abs/1508.04101 https://arxiv.org/abs/1508.04101 Brasil, Understanding the Pointer States
- konschubert 5y agoOkay, cool, I’m 100% with you. But could we then please stop teaching the collapse nonsense to first year students? The logical inconsistencies of the collapse interpretation are an insult to their intellect.
- orbifold 5y agoThe collapse just stands for the unknowable details of the interaction with the environment during measurement, a good quantum physics course will explain that and include experiments that make that clear. For instance the Stern-Gerlach experiment illustrates this well.
- GoblinSlayer 5y agoDecoherence is a consequence of interaction between particles in the coherent state, environment plays no role there, you can do all experiments in the vacuum and they will still work the same way, obviously.
- l33tman 5y agoDecoherence theory is really somewhat orthogonal to the measurement problem. Decoherence explains how the "collapse" happens gradually if you have a non-perfectly isolated system by seeping entanglement. But at some point you still need to activate the stipulation that you as an observer is drawn into the entanglement and at that point whatever's left of the wavefunction "collapses". In essence the Copenhagen interpretation is still correct as a simplification that can still be OK in most cases. This is reflected by the fact that practising solid state physicists have successfully used this 20's style of QM for 100 years now.