3 ms·
It's more akin to how on Intel, each core's L2 has some maximum bandwidth to LLC, and can't individually saturate the total bandwidth available on the ring bus.
by brigade 5y ago
It's more akin to how on Intel, each core's L2 has some maximum bandwidth to LLC, and can't individually saturate the total bandwidth available on the ring bus. But Intel doesn't have the LLC <-> RAM bandwidth for that to be generally noticeable.