4 ms·
85 grams of DNA contain around 8 * 10^22 base pairs, 2 bits per pair, so around 2 * 10^22 bytes. So you need about 75 bits to address all these bytes. I do not
by d_tr 5y ago
85 grams of DNA contain around 8 * 10^22 base pairs, 2 bits per pair, so around 2 * 10^22 bytes. So you need about 75 bits to address all these bytes.
I do not know why Laremere chose 85.8 grams though as these are quite above the 64 bit limit, unless I got my multiplications wrong :P
- sdenton4 5y agoNot that anything uses that much DNA, anyway: "The male nuclear diploid genome extends for 6.27 Gigabase pairs (Gbp), is 205.00 cm (cm) long and weighs 6.41 picograms (pg)." Or, many many orders of magnitude less than 85 grams...