> Or for something simple > y(t) = { y(0) b e^{bkt} \over y(0) \big ( e^{bkt} - 1 \big ) + b} TeXmacs finds that, by the way. I just tested it. And each piece

> Or for something simple > y(t) = { y(0) b e^{bkt} \over y(0) \big ( e^{bkt} - 1 \big ) + b} TeXmacs finds that, by the way. I just tested it. And each piece of it: I tested the denominator.