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So it’s not specific to functions as arguments? A long-time gripe I’ve had about default parameters in Python is that they are static from function definition t

So it’s not specific to functions as arguments? A long-time gripe I’ve had about default parameters in Python is that they are static from function definition time instead of dynamic at call time. A consequence of that is that if you have a function like def foo(bar, baz=[]): baz.append(bar) return baz baz will be reused for the duration of the process kind of like a global variable. If this new syntax fixes that, I see the value.

Sohcahtoa82 5y ago
> If this new syntax fixes that, I see the value. It does. The old syntax creates and assigns the variable at compile-time. => does it at execution time. So this code: def foo(bar, baz=[]): baz.append(bar) return baz foo(1) foo(2) print(foo(3)) would print '[1, 2, 3]' But this code: def foo(bar, baz=>[]): baz.append(bar) return baz foo(1) foo(2) print(foo(3)) would print '[3]'