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You can make some progress by thinking of the imaginary numbers as being a two dimensional vector space over the reals, equipped with a very peculiar multiplica
by wrycoder 5y ago
You can make some progress by thinking of the imaginary numbers as being a two dimensional vector space over the reals, equipped with a very peculiar multiplication operator that is a combination of the usual stretch with a rotation.
Addition is the usual addition of components, but the multiplication (using polar coordinates) looks like
C = ABexp(T1+T2),
where the T are the phases of A and B.
To multiply two positive reals, since their phases are zero, it’s only a stretch: AB
To multiply two negative reals, since their phases are pi, it’s ABexp(pi+pi). But exp(2pi) is unity, so we have AB again, a positive number.
To find the square root of a positive number D, find a positive real (zero phase) that, when multiplied by itself, gives D. AA, for example.
So, real number arithmetic is a subset of complex number arithmetic, with zero phase. And therefore zero rotation.
Now, find the square root of a negative number, say -4. To do this, we have to step off the real axis for the first time: out into the Argand plane!
-4 is represented as
4exp(pi)
OK?
So we are looking for a number out here on the Argand plane that when multiplied by itself following our rule gives 4exp(pi).
And that number is
2exp(pi/2),
which is two units out on the “imaginary” axis of our Argand plane.
2exp(pi/2)2exp(pi/2)
equals 4exp(pi/2+pi/2)
equals 4exp(pi)
QED