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> I’ve split the specular and diffuse components with polarization so the diffuse is on the left and the specular is on the right. Does this mean the author t
by jerry1979 5y ago
> I’ve split the specular and diffuse components with polarization so the diffuse is on the left and the specular is on the right.
Does this mean the author took two pictures: one with a polarization lens, and a second with the same polarization lens rotated 90 degrees?
I'm vaguely interested in what's going on here. For others who are interested, I think this reddit post has some technical details which relate to the topic: https://www.reddit.com/r/photogrammetry/comments/mfle5u/how_to_capture_specularroughness_maps/ https://www.reddit.com/r/photogrammetry/comments/mfle5u/how_...
- _Microft 5y agohttps://old.reddit.com/r/photogrammetry/comments/mfle5u/how_to_capture_specularroughness_maps/ https://old.reddit.com/r/photogrammetry/comments/mfle5u/how_...
- aktenlage 5y agoAnd if so, what does it mean? I have no idea what that split is supposed to illustrate and how the image would have looked without a filter.
- twelvechairs 5y agoIts done to split out clearly technically. Right is the specular component, left is excluding the specular component. Right us basically if you shined a very bright light exactly from the angle of reflection. Left is more similar to if the scene had background lighting but not from the angle of reflection
- Jasper_ 5y agoSee this follow-up post http://filmicworlds.com/blog/how-to-split-specular-and-diffuse-in-real-images/ http://filmicworlds.com/blog/how-to-split-specular-and-diffu...