62 ms·
I'm not sure, but I think it represents uncertainty over the last digits. So 1.000051(29) would be equivalent to 1.000051 +- 0.000029.
by BoppreH 15y ago
I'm not sure, but I think it represents uncertainty over the last digits.
So 1.000051(29) would be equivalent to 1.000051 +- 0.000029.
- kaybe 15y agoYes, that is what it means. :)
- jlarocco 15y agoThat can't be it because the error wouldn't straddle the speed of light. It would put the range at 1.000022c to 1.000080c, both of which exceed c, so they wouldn't have written it off as error.
- Ralith 15y agoBut that doesn't indicate a hard error bound; this is a statistical matter, after all. Most likely it's just an expected standard deviation.
- Bootvis 15y agoIt indeed is the standard deviation.
- kaybe 15y agoA single standard deviation is not enough, normal procedure is to allow up to three standard deviations (or more, sometimes five), which puts the measurement in a range consistent with models.