> There is no procedural concepts like variable assignment allowed in a python lambda. Just a small note that the walrus operator gives you some wiggle room he

> There is no procedural concepts like variable assignment allowed in a python lambda. Just a small note that the walrus operator gives you some wiggle room here: add_5_to_square_if_greater_than_10 = lambda x: squared + 5 if (squared := x * x) > 10 else x assert add_5_to_square_if_greater_than_10(2) == 2 assert add_5_to_square_if_greater_than_10(5) == 30