3 ms·
I don't understand what you mean by duplicate here. Apply a Schwartzian Transform and there you go -- no duplicates.
by Quekid5 5y ago
I don't understand what you mean by duplicate here. Apply a Schwartzian Transform and there you go -- no duplicates.
- JohnHaugeland 5y agothe decorate sort undecorate is more expensive than the thing you're trying to save
- Quekid5 5y agoThat doesn't make sense. The Schwartzian Transform is linear time and cheap time-wise. Btw, I'm surprised nobody has objections about constants. The constants for the type of stuff 'discrimination' does are (apparently) really bad. Like really bad. ^ The above was a bit sarcastic. I know you're talking about straight up performance, but the problem there wouldn't be the Schwartzian Transform.