3 ms·
This doesn't work. Even if you assume sqrt(a) + sqrt(b) > sqrt(c) + sqrt(d), that doesn't necessarily mean that log(sqrt(a)) + log(sqrt(b)) > log(sqrt(c)) + log
by 3PS 5y ago
This doesn't work. Even if you assume sqrt(a) + sqrt(b) > sqrt(c) + sqrt(d), that doesn't necessarily mean that log(sqrt(a)) + log(sqrt(b)) > log(sqrt(c)) + log(sqrt(d)). For example, let a = 1, b = 100, c = 25, d = 25. Then
> sqrt(1) + sqrt(100)
11.0
> sqrt(25) + sqrt(25)
10.0
> log(sqrt(1)) + log(sqrt(100))
2.302585092994046
> log(sqrt(25)) + log(sqrt(25))
3.2188758248682006