3 ms·
They specified that in the post, they were able to constrain to a strategy that guarantees 6 or fewer and then optimize for EV to get 3.55, but could get down t
by furyofantares 5y ago
They specified that in the post, they were able to constrain to a strategy that guarantees 6 or fewer and then optimize for EV to get 3.55, but could get down to 3.52 by allowing some small number of words to take more than 6.
I would be interested to know if 6 is the lowest you can constrain it. Can you guarantee a solution in 5, and if so what is the best EV with that constraint?
- npinsker 5y agoYes, you can -- I believe the EV was around 3.47 for that. The "greedy" strategy (minimizing the worst-case size of the largest set) also ends up using at most 5 words. Perhaps unsurprisingly, you can't guarantee at most 4 words.
- Sesse__ 5y agoYou can get EV of 3.46393 with a guaranteed maximum of five tries. (I don't know whether this bound is tight.)
- pxx 5y agoThis bound is not tight. http://sonorouschocolate.com/notes/index.php?title=The_best_strategies_for_Wordle http://sonorouschocolate.com/notes/index.php?title=The_best_...
- Sesse__ 5y agoGood to know. Another possible question is: What is the best strategy minimizing (at any point) _first_ the maximum number of tries, and second the EV (average number of tries over all possible words)? That's subtly different from either answer.