4 ms·
My simple solution was: - Use a normal d5 and d6. - On a roll, if the sum on the dice face is >= 7, add 1 to the sum. If I roll 2+3, the result is 5. If I ro
by quacker 5y ago
My simple solution was:
- Use a normal d5 and d6.
- On a roll, if the sum on the dice face is >= 7, add 1 to the sum.
If I roll 2+3, the result is 5. If I roll 3+4, the sum is 7, so add 1 to get the result of 8.
The gives you this distribution, and is simple in practice.
1 2 3 4 5
1 2 3 4 5 6
2 3 4 5 6 8
3 4 5 6 8 9
4 5 6 8 9 10
5 6 8 9 10 11
6 8 9 10 11 12