3 ms·
Ah yes, that's correct - I believe that reading and comparing the padding bytes results in undefined behavior - the bytes might not actually be initialized dep
by vgatherps 5y ago
Ah yes, that's correct - I believe that reading and comparing the padding bytes results in undefined behavior - the bytes might not actually be initialized depending on the object class. I also don't know if you can actually use the result of comparing an unspecified/implementation defined/indeterminate value - that's where poison is generated.
In practice (UB aside), this is basically fine in the context of a read, compute, CAS loop. Those bytes do have some value in the machine and if that memory isn't written they won't mysteriously change. It's playing games with the optimisers and UB however. You might be able to get around this by first initialising the bytes to zero, then in-place copy constructing whatever you want? I wouldn't bet anything serious on that being defined though.
- klodolph 5y agoThe poison is only generated with indeterminate values in objects with automatic storage duration (local variables on the stack). Padding bytes in other circumstances will have specific, valid values and can be compared. (An "indeterminate value" is an unspecified value or a trap representation, unsigned char does not permit trap representations, and unspecified values are "valid values".) Use of other unspecified values results in "unspecified behavior" which does not result in trimming the CFG. I think the spec is written this way to codify how compilers are allowed to do liveness analysis... a local variable is marked as live when it is initialized, and if a variable is not live, its storage (registers or stack) may be used for other variables or temporary values. You then get UB because, for example, two comparisons may result in contradictory outcomes, because the value has been overwritten with garbage between the two comparisons. Or in a more modern compiler, you read from an uninitialized local variable, and the compiler trims the CFG. Here's an example of what I'm thinking of: int x, y; // point A if (condition) { x = 5; } else { y = 10; } // point B A compiler can realize that x and y can't both be live at the same time, and assign them to the same register or stack location. However, this means that if you read the value of x at point A and point B, but x is uninitialized, it will naturally have a different value each time you use it... because the value of Y is overwriting it!