3 ms·
I don't understand. If you can turn the loop from upward to downward then you do have a bound for it, and then you can tell if it overflows or not. Also why i
by hramrach 5y ago
I don't understand.
If you can turn the loop from upward to downward then you do have a bound for it, and then you can tell if it overflows or not.
Also why is signed overflow a problem and not unsigned?
Surely you want unsigned loop optimized also?
- astrange 5y agoUnsigned overflow is not UB (it wraps) so it has to be preserved more often, which means you have a loop bounds less often, which means those loops can't be optimized. Typically not a problem for i=0...n loops but eg `for (i=0;i<n;i+=2)` could overflow.