3 ms·
Actually, here: 0. li:first-child 1. p:not(.foo) 2. li:nth-child(2n+3) 3. div > * 4. span[data-item] 5. p ~ span 6. form > *:enabled 7. #one, #two, #fiv
by soperj 5y ago
Actually, here:
0. li:first-child
1. p:not(.foo)
2. li:nth-child(2n+3)
3. div > *
4. span[data-item]
5. p ~ span
6. form > *:enabled
7. #one, #two, #five, #six, #nine
8. a + span
9. #foo > .foo
10. div > div > span + code:not(.foo)
- tiffanyh 5y agoThanks so much!
- soperj 5y agoNo worries. There's lots of documentation, but happy to help if you have a specific question.
- mcv 5y ago> li:nth-child(2n+3) I was not aware of this. I did li:nth-child(3), li:nth-child(5), li:nth-child(7) but was thoroughly unhappy about it. Thanks for showing the better solution.
- Vincenius 5y agoNice - for 6. I had just *:enabled, but other that that those are exactly the solutions I thougt of when creating the puzzles :)
- soperj 5y agoI guess I just habitually make things more specific incase i need to overwrite them. This was really fun. Thanks for making it :)