3 ms·

Why parts of the instruments need to be cooled below 50K? Do they have quantum computers on the JWST?

echelon 5y ago
Since JWST is trying to pick up weak infrared signal from the furthest reaches of the cosmos, any amount of noise would distort our measurements. The telescope itself will naturally radiate infrared heat (much like our own bodies do), which is exactly what the instrument is trying to measure. This is why they're cooling the instrumentation side to such a cold temperature that it won't emit infrared energy and ruin the science.
- octocop 5y ago
  Allright, so is that why it takes ~6 months of waiting time now? Would it not be possible to just measure the heat radiated from JWST and subtract it from readings?
  - vlovich123 5y ago
    Sensors that can measure the heat will themselves be putting out their own heat. The scientists who built this thing are pros.
  - jakeinspace 5y ago
    Measure thermal noise? The amount of information contained in the black body radiation of a warm (well, really cold, but not cold enough) object must be absolutely immense, at least when you care about a signal at the level of single photons. Trying to capture it with sensors is futile. Sure you can try to do some noise suppression with a simplified model/probability distribution, but that won't work well if your signal to noise ratio is 0.00001.
  - koziserek 5y ago
    That would be like throwing a beam of a light from a powerful flashlight 10 cm away from his face when he watches night scenes from last season of Game of Thrones, and saying ”just ignore these 1000 lumens, tell me what is happening?”
Fronzie 5y ago
The detectors themselves, to reduce thermal noise. It is not uncommon to cool down sensitive detectors, for example, in electron microscopes, the x-ray detectors are typically cooled down below -40 Celsius.
Redoubts 5y ago
Things in and around the infrared sensors, since warm objects would blind the sensors with black-body radiation
pkaye 5y ago
There are a couple of instruments that are passively cooled but one instrument the MIRI needs active cooling down to 6.7K.

Since JWST is trying to pick up weak infrared signal from the furthest reaches of the cosmos, any amount of noise would distort our measurements. The telescope itself will naturally radiate infrared heat (much like our own bodies do), which is exactly what the instrument is trying to measure. This is why they're cooling the instrumentation side to such a cold temperature that it won't emit infrared energy and ruin the science.

octocop 5y ago
Allright, so is that why it takes ~6 months of waiting time now? Would it not be possible to just measure the heat radiated from JWST and subtract it from readings?
- vlovich123 5y ago
  Sensors that can measure the heat will themselves be putting out their own heat. The scientists who built this thing are pros.
- jakeinspace 5y ago
  Measure thermal noise? The amount of information contained in the black body radiation of a warm (well, really cold, but not cold enough) object must be absolutely immense, at least when you care about a signal at the level of single photons. Trying to capture it with sensors is futile. Sure you can try to do some noise suppression with a simplified model/probability distribution, but that won't work well if your signal to noise ratio is 0.00001.
- koziserek 5y ago
  That would be like throwing a beam of a light from a powerful flashlight 10 cm away from his face when he watches night scenes from last season of Game of Thrones, and saying ”just ignore these 1000 lumens, tell me what is happening?”

Fronzie 5y ago

The detectors themselves, to reduce thermal noise. It is not uncommon to cool down sensitive detectors, for example, in electron microscopes, the x-ray detectors are typically cooled down below -40 Celsius.

Redoubts 5y ago

Things in and around the infrared sensors, since warm objects would blind the sensors with black-body radiation

pkaye 5y ago

There are a couple of instruments that are passively cooled but one instrument the MIRI needs active cooling down to 6.7K.