2 ms·

I completely get that. That is a very nice feature for building DSL or libraries with special needs. But it makes the overall language very dangerous. Is this

by oaiey 5y ago

I completely get that. That is a very nice feature for building DSL or libraries with special needs. But it makes the overall language very dangerous. Is this "operator" overloadable on each type in Python? And that scares me a lot. I think I have to reevaluate my position towards Python.

housecarpenter 5y ago
It's not really an operator. It's part of the syntax of string literals. "foo" "bar" is an alternative way of writing the string literal "foobar". If foo is not a string literal, foo "bar" is invalid syntax.
- oaiey 5y ago
  Okay... So it is not a implicit operator. That is good. Some small reputation points are regained. Thanks.