Nope. Whenever you use (), the parser assumes a method call. sqr, inc and (sqr * inc) are not methods (but Proc objects), and all you can do is call _their_ met

Nope. Whenever you use (), the parser assumes a method call. sqr, inc and (sqr * inc) are not methods (but Proc objects), and all you can do is call _their_ methods, such as [].