3 ms·x/x = 1 for all x except 0; defining 0/0 = 1 removes that exception.by AlbinNP 5y agox/x = 1 for all x except 0; defining 0/0 = 1 removes that exception.hwayne 5y agoSplit the difference, 0/0 = 0.5ben_w 5y agoIt gets worse: differentiation would be 0/0 if you went straight to the limit rather than just approaching it, so 0/0 can be any differentiable function, not just a value. (Caveat: I’m probably being slightly imprecise with my language here)