4 ms·
What you do mean ugly :) [{"thing": k, "count": v} for k, v in [[c, c.update({x["thing"]: x["count"]})] for c in [Counter()] for x in response][0][0].items()]
by runekaagaard 5y ago
What you do mean ugly :)
[{"thing": k, "count": v} for k, v in [[c, c.update({x["thing"]: x["count"]})] for c in [Counter()] for x in response][0][0].items()]