3 ms·

I don't think it's fair to call out since no one is putting a println! in hot loops unless they're debugging

• brundolf 5y ago
  Not remotely true. I learned this lesson the hard way a couple years ago while working on a program that did exactly that.
  • duped 5y ago
    Why were you calling println in a hot loop instead of using a logging library?
    • brundolf 5y ago
      Because it was a simple CLI tool that spit out a bunch of output as part of its core functionality.