3 ms·
You probably mean E = 1/2 m v^2 https://en.wikipedia.org/wiki/Kinetic_energy#Kinetic_energy_of_rigid_bodies https://en.wikipedia.org/wiki/Kinetic_energy#Kinetic
by johndough 5y ago
You probably mean E = 1/2 m v^2 https://en.wikipedia.org/wiki/Kinetic_energy#Kinetic_energy_of_rigid_bodies https://en.wikipedia.org/wiki/Kinetic_energy#Kinetic_energy_...
- epgui 5y agoYou can harmlessly spread a lot of energy difference over a large enough time, or a large enough surface. The most relevant concepts are probably impulse [1] and inelastic collision [2]. [1] https://en.wikipedia.org/wiki/Impulse_(physics) https://en.wikipedia.org/wiki/Impulse_(physics) [2] https://en.wikipedia.org/wiki/Inelastic_collision https://en.wikipedia.org/wiki/Inelastic_collision
- antisthenes 5y agoAh, yes. The perils of making comments at 2 AM. I stand corrected.