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I tested and seems, that x is the first implicit parameter, y - second, z - third. It is as stated in their online documentation. When you try following example
by rabarbers 5y ago
I tested and seems, that x is the first implicit parameter, y - second, z - third. It is as stated in their online documentation.
When you try following example:
{y+x*z}[1;2;3]
It gives result:
5
And in Q you cannot define implicit parameters with names, for example,: a, b, c. But You can define parameters explicitly:
{[a;b;c]a+b*c}[1;2;3]
I still think that their implicit parameters are keywords. Similarly as keyword 'it' in Kotlin programming language is used to refer to the single parameter of the lambda expression.
In KatLang there are no predefined implicit parameter names. The user is the one who defines implicit parameters by declaring the implicit parameter names.
- geocar 5y agoNo. They are not keywords. The program: x:42; f:{[a]x+a} is the same as: x=42; f=function(a){return x+a}
- rabarbers 5y agoThanks for explaining! But how about this example: x:42 {x+1}[5] It results in 6 It seems like you can define variables with the name 'x', but when you do not have explicit parameters, then the identifier 'x' is used to refer to the first implicit parameter, y - for second and z - for the third parameter. In context of implicit parameters x, y and z acts like predefined keywords.
- geocar 5y agoq's functions don't capture the environment, so that's the same as: a:42 {[a]a+1}[5] and as in javascript: a=42; f=function(a){return a+1} and when i say they don't capture the environment, i mean this: f:{[g] {g+x}} doesn't do anything except generate errors (° there are benefits to this approach!) because the inner function (that we are returning) sees the "global" g and not the one lexically scoped in the function (a better way to say it: no closures).