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I'm being honest here. Reading along I randomly picked 987 from my brain. I scrambled that to 897. Subtracting the smaller from the larger I got 90, per the i
by icameron 5y ago
I'm being honest here. Reading along I randomly picked 987 from my brain. I scrambled that to 897. Subtracting the smaller from the larger I got 90, per the instructions. So I am unable to tell you the remaining digits starting with a number that isn't 9 or 0.... Maybe I'm a "you must be fun to talk to at parties" kind of guy.
- leecarraher 5y agoyeah for first 10000 digits there is about a 2%-5% chance (around 20%-5% for first 2k, then falls below 2% for remaining 2/3s) of selecting one that doesn't work. obviously picking something like 1111, 2222, ... won't work either since you can't rearrange it to anything but 0s.
- cphoover 5y agolol
- coldpie 5y agoI did the same thing, starting from 100. I guess maybe "no digits" is a sufficient response to end up with 90?
- kej 5y agoAlthough not mentioned in the article, the trick can handle this. The rule should be "remove a digit that isn't 0", and if the sum of remaining digits is divisible by 9 then the removed digit must be 9 as well. That will cover everything except the case when the original number and the scrambled number are the same.
- LocalH 5y agoYour remaining digits are NaN