4 ms·
Sorry I don't have a reference, but as long as you are outside of an object, its gravitational force on you is the same as if it were a point-mass (at least for
by muyyatin 15y ago
Sorry I don't have a reference, but as long as you are outside of an object, its gravitational force on you is the same as if it were a point-mass (at least for classical physics).
- xsmasher 15y agoWhich points to the oceans "bunching up," not laying flat.
- bzbarsky 15y agoThis is only true for objects that have a spherically symmetrical mass distribution and for a point test object. That is, the field of a spherically symmetric object is the same as the field of a point mass of its mass located at its center. As soon as your test object is non-point you get tidal forces due to the field typically being nonuniform. As soon as your object is not spherically symmetric you get a field that looks nothing like that of a point mass.
- starwed 15y agoIt's still the case that if you're sufficiently far away from a nonspherical object, it'll effectively act like a point source. I'd guess this is what the OP was recalling.
- bzbarsky 15y agoWell, sure. If you're far enough away it _looks_ like a point source! That doesn't apply to being on the face of a cube, though; that's not nearly far enough away, obviously. :)