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Yeah, I've read that. But this is not an open standard, it's just a hack, and it is under the control of a vendor. Worse, it is nothing but a thin layer above
by ur-whale 5y ago
Yeah, I've read that.
But this is not an open standard, it's just a hack, and it is under the control of a vendor.
Worse, it is nothing but a thin layer above an even more proprietary layer.
- chmod775 5y ago> But this is not an open standard, it's just a hack, and it is under the control of a vendor. It's under a permissive license (MIT). What makes you say it is "just a hack"? What makes it a hack? > Worse, it is nothing but a thin layer above an even more proprietary layer. The same is true for OpenCL (layer above a proprietary layer) and pretty much any API interfacing with proprietary hardware/drivers. Also it's not even proprietary software in the first place, even if you're trying to make it sound that way.