3 ms·
Fun digression late on a Wednesday :) The indeterminate form seems the most correct based on the analysis of the limit of f(x,y) = x^y as x approached zero fro
by 3am 15y ago
Fun digression late on a Wednesday :)
The indeterminate form seems the most correct based on the analysis of the limit of f(x,y) = x^y as x approached zero from different paths.
I had always thought of it more of an algebraic identity thing; x^n * x^m = x^(n+m). Obviously x^(n) = x^(n+0) = x^n * x^0 which can only be satisfied if x^0 = 1. But this article (and really, the wikipedia treatment that beej71 linked to) made me think more about it.
- Someone 15y ago"Obviously x^(n) = x^(n+0) = x^n * x^0 which can only be satisfied if x^0 = 1." ...or if x^n = 0, which is true if x=0 and n != 0