3 ms·
I think it is easier to extend a polynomial multiplication (known concept) with a finite field than to directly introduce a carryless multiplication. Also there
by lifthrasiir 5y ago
I think it is easier to extend a polynomial multiplication (known concept) with a finite field than to directly introduce a carryless multiplication. Also there are multiple different bitwise representations for the same polynomial, so separating them might avoid some confusion.
- superjan 5y agoThanks. I suppose that there is value in expressing the operations in a form that all agree is well defined.