3 ms·
What danachow said makes sense to me. Under the "Logarithms and exponential" heading, it says the operator chip uses an exponential look-up room to convert thi
by thegardengnome 5y ago
What danachow said makes sense to me. Under the "Logarithms and exponential" heading, it says the operator chip uses an exponential look-up room to convert this value back to a linear value. "This value" here refers to the output of log2(x*y). So I think it's implied that yes, the log2 calculation will yield a floating point number, but that floating point number will be converted back to a phase increment value that corresponds to the LUT. This is my shallow understanding of things