4 ms·
Yet another reason is all the references in LHS expressions are resolved before the inner expression is executed. Thus a['k'] = a = {} won't still work.
by oshiar53-0 5y ago
Yet another reason is all the references in LHS expressions are resolved before the inner expression is executed. Thus
a['k'] = a = {}
won't still work.
- xg15 5y agoYou mean in JS? Good to know, I wasn't aware of that.