4 ms·
Spins are so short and well-defined that I wonder why the kernel doesn't just examine a handful of instructions around the program counter and guess if the thre
by dataflow 5y ago
Spins are so short and well-defined that I wonder why the kernel doesn't just examine a handful of instructions around the program counter and guess if the thread is spinning or not before scheduling it for another time slice. Seems like a really nice and simple kind of heuristic to implement.
- jlokier 5y agoYour idea works well for other kinds of more abstract critical sections too, such as code regions where a garbage collection should be temporarily deferred. Or in embedded systems where code is running at supervisor level, regions where an interrupt should be deferred, thereby allowing interrupt-disable and interrupt-enable instructions to be avoided. An alternative which is reasonably fast on modern CPUs is to have a spinlock implementation in the kernel VDSO (or equivalent). Something a bit like that was done in uCLinux for old ARMs, except instead of a spinlock, they put atomic compare-and-swap in the VDSO, as the CPU didn't have an instruction for that. The kernel checked the userspace address on interrupts, and altered the PC register to redo the compare if the sequence was interrupted. So that didn't extend the timeslice to allow the operation to complete. Instead it unwound the operation to ensure correct semantics. With a spinlock/mutex combination, cutting short the spinning phase when the task is descheduled by the kernel would be similar, and would allow the "normal" spin count to be unlimited.
- monocasa 5y agoOh jeeze, I don't think there'd be anything simple about having to divine facts about user space by the code flow graph near the interrupted instruction on basically every thread switch.
- remexre 5y agoMaybe hardware support would make it viable, at least at an academic level.
- dataflow 5y agoYou don't need to worry about the CFG here, a spinlock is literally just a ~4-instruction loop (or a few more, depending on the form you use). All you need is to handle a few common codegen patterns. Like if you see the instruction pointer in the middle of a mov + xchg + test + jne sequence then you know it's a spinlock. If you don't detect it in some canonical form then you're back where we are now; whatever. It's not complicated.
- monocasa 5y agoThe issue with spin locks isn't the lock sequence itself, it's the code between it being locked and unlocked.
- dataflow 5y agoI'm not sure which issue you're referring to, but the one I was trying to address was the one above about the spinning itself causing a priority inversion: "you now have a descheduled thread that owns the lock and a spinning thread waiting to acquire it, which is a recipe for priority inversion."
- monocasa 5y agoA) it's not just a priority inversion. The problem happens with simple round robin schedulers too. B) The problem is the descheduled thread which has the lock and isn't in the lock sequence. Simply killing the time slice of the spinning thread without knowing what it's waiting on may lead to even worse behavior. The answer here is simple: just don't use pure spinlocks if you can be preempted.
- dataflow 5y ago> it's not just a priority inversion. Did I claim it was...? > Simply killing the time slice of the spinning thread without knowing what it's waiting on may lead to even worse behavior. It's not obvious to me how likely this is compared to the other case, but if you're trying to make a case for why a kernel doing that would result in worse behavior in typical cases, it would probably help to explain this. > The answer here is simple: just don't use pure spinlocks if you can be preempted. I don't get why you're arguing with me on this. I wasn't telling anyone to use spinlocks, nor claiming this is the one and only problem with spinlocks. I was just saying a kernel could be a little smarter about a particular case by examining the instruction sequence.