Unless I'm mistaken, this is almost, but not quite correct. (Firstly, what's being cast is `p` which is a `void-pointer`.) More importantly, the latter cast say

Unless I'm mistaken, this is almost, but not quite correct. (Firstly, what's being cast is `p` which is a `void-pointer`.) More importantly, the latter cast says to treat p as a `pointer to an array of int-pointers`, which means that the first dereference actually gives you the array. Expressions with an array type in most contexts (including this one) decay into pointers to their first elements – thus the second dereference gets you the first element of the array, an int-pointer, and the third one gets you the integer being pointed to. Also, because this array type is incomplete (it has no size), I don't think you could use it in any context where it didn't "decay" into a pointer to its first element (you can test what your compiler says if you try to measure the array's size with the sizeof operator when only using one dereference).