Does that mean this: Array(n).fill() is a permanent deoptimization? And if so, is the new array returned by: Array(n).fill().map(x => x) better opti

Does that mean this: Array(n).fill() is a permanent deoptimization? And if so, is the new array returned by: Array(n).fill().map(x => x) better optimized (after the, presumably, suboptimal iteration)?