It breaks the expectation of programmers that operators in PEMDAS (or whatever you call it) are evaluated how you expect. If I type: d = a + b * c I expec

It breaks the expectation of programmers that operators in PEMDAS (or whatever you call it) are evaluated how you expect. If I type: d = a + b * c I expect it to be evaluated as: d = a + (b * c) Maybe that’s just me, but I bet I’m not the only one that thinks that way. For non math operators, you may have a point…