46 ms·
It is a mistake. The bomb does not damage a radius, it damages an area which is quantified by a radius squared. Again, this is high school geometry, not contr
by skyechurch 5y ago
It is a mistake. The bomb does not damage a radius, it damages an area which is quantified by a radius squared. Again, this is high school geometry, not controversial, and maybe there are factors not explained which make this correct in a sense (maybe "damage" is a term of art which varies by the square root of area destroyed? Seems unintuitive, but I'm not an expert in atom bombs or much of anything.)
It's a silly error which in no way undercuts anything in the article afaict, but it annoys because it is very simple and obviously true by unit analysis. I make silly errors too, as we all do, present company excepted. But it does undercut my confidence in the more far difficult journalistic work being done, which I cannot interrogate with my limited mathematical skills and pretty much have to take on faith. To me it speaks to the question of whether I "learned something" or "read some words".
This is a very boring digression and I take full responsibility for making a ticky-tacky point, which I have now I believe fully explained and contextualized.
- pdoege 5y agoI don't think it is true that bombs damage an area. For example, when I worked on ADF nukes we were interested in the volumes necessary to destroy targets located in 3D airspace. Similarly underwater explosions caused spherical and columnar affects depending on yield and depth.
- CJefferson 5y agoI bomb exploded near the surface of the earth will, in effect, explode as a hemisphere, which is why there is a cube root. If you could somehow make the force spread only over the surface of the earth it would be radius squared, but that isn't what happens -- most of it goes into the air. You could think about what would happen in space (a spherical explosion), then consider what would happen as it got closer to the earth.
- skyechurch 5y ago>In evaluating the destructive power of a weapons system, it is customary to use the concept of equivalent megatons (EMT). Equivalent megatonnage is defined as the actual megatonnage raised to the two-thirds power: >EMT = Y[^]2/3 where Y is in megatons. >This relation arises from the fact that the destructive power of a bomb does not vary linearly with the yield. The volume the weapon's energy spreads into varies as the cube of the distance, but the destroyed area varies at the square of the distance. Src: https://www.atomicarchive.com/science/effects/energy.html https://www.atomicarchive.com/science/effects/energy.html It's just geometry, or dimensionality, you cannot directly compare 1D and 2D quantities. Type mismatches are often bad in programming, but always fatal in physics.